【題解】Zerojudge f282 - 松鼠的願望

題目大意

將範圍為 $1 \sim 100$ 的數字排序並輸出。時限很緊,要優化 IO。

題解

排序小範圍的數字可以用 Counting Sort,請參考【題解】Zerojudge c431 - Sort ! Sort ! Sort ! 的題解。IO 優化的相關技巧請參考我的【筆記】IO 優化這篇文章,以下的程式碼是使用該文章中所提到的 tourist IO。
#include <bits/stdc++.h>
using namespace std;

namespace std {

static struct FastInput {
	static constexpr int BUF_SIZE = 1 << 20;
	char buf[BUF_SIZE];
	size_t chars_read = 0;
	size_t buf_pos = 0;
	FILE *in = stdin;
	char cur = 0;

	inline char get_char() {
		if(buf_pos >= chars_read) {
			chars_read = fread(buf, 1, BUF_SIZE, in);
			buf_pos = 0;
			buf[0] = (chars_read == 0 ? -1 : buf[0]);
		}
		return cur = buf[buf_pos++];
		// return cur = getchar_unlocked();
	}

	inline void tie(int) {}

	inline explicit operator bool() { return cur != -1; }
	inline static bool is_blank(char c) { return c <= ' '; }

	inline bool skip_blanks() {
		while(is_blank(cur) && cur != -1) {
			get_char();
		}
		return cur != -1;
	}

	inline FastInput& operator>>(char& c) {
		skip_blanks();
		c = cur;
		return *this;
	}

	inline FastInput& operator>>(string& s) {
		if(skip_blanks()) {
			s.clear();
			do {
				s += cur;
			} while(!is_blank(get_char()));
		}
		return *this;
	}

	template<class T>
	inline FastInput& read_integer(T& n) {
		n = 0;
		if(skip_blanks()) {
			int sign = +1;
			if(cur == '-') {
				sign = -1;
				get_char();
			}
			do {
				n += n + (n << 3) + cur - '0';
			} while(!is_blank(get_char()));
			n *= sign;
		}
		return *this;
	}

	template<class T> inline typename enable_if<is_integral<T>::value, FastInput&>::type operator>>(T& n) { return read_integer(n); }
	inline FastInput& operator>>(__int128& n) { return read_integer(n); }

	template<class T>
	inline typename enable_if<is_floating_point<T>::value, FastInput&>::type operator>>(T& n) {
		n = 0;
		if(skip_blanks()) {
			string s;
			(*this) >> s;
			sscanf(s.c_str(), "%lf", &n);
		}
		return *this;
	}
} fast_input;

#define istream FastInput
#define cin fast_input

static struct FastOutput {
	static constexpr int BUF_SIZE = 1 << 20;
	char buf[BUF_SIZE];
	size_t buf_pos = 0;
	static constexpr int TMP_SIZE = 1 << 20;
	char tmp[TMP_SIZE];
	FILE *out = stdout;
 
	inline void put_char(char c) {
		// buf[buf_pos++] = c;
		// if(buf_pos == BUF_SIZE) {
		// 	fwrite(buf, 1, buf_pos, out);
		// 	buf_pos = 0;
		// }
		putchar_unlocked(c);
	}

	~FastOutput() {
		// fwrite(buf, 1, buf_pos, out);
	}

	inline FastOutput& operator<<(char c) {
		put_char(c);
		return *this;
	}

	inline FastOutput& operator<<(const char* s) {
		while(*s) {
			put_char(*s++);
		}
		return *this;
	}

	inline FastOutput& operator<<(const string& s) {
		for(int i = 0; i < (int) s.size(); i++) {
			put_char(s[i]);
		}
		return *this;
	}

	template<class T>
	inline char* integer_to_string(T n) {
		char* p = tmp + TMP_SIZE - 1;
		if(n == 0) {
			*--p = '0';
		} else {
			bool is_negative = false;
			if(n < 0) {
				is_negative = true;
				n = -n;
			}
			while(n > 0) {
				*--p = (char) ('0' + n % 10);
				n /= 10;
			}
			if(is_negative) {
				*--p = '-';
			}
		}
		return p;
	}

	template<class T> inline typename enable_if<is_integral<T>::value, char*>::type stringify(T n) { return integer_to_string(n); }
	inline char* stringify(__int128 n) { return integer_to_string(n); }

	template<class T>
	inline typename enable_if<is_floating_point<T>::value, char*>::type stringify(T n) {
		sprintf(tmp, "%.17f", n);
		return tmp;
	}

	template<class T>
	inline FastOutput& operator<<(const T& n) {
		auto p = stringify(n);
		for(; *p != 0; p++) {
			put_char(*p);
		}
		return *this;
	}
} fast_output;

#define ostream FastOutput
#define cout fast_output

} // namespace std

int main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	vector<int> cnt(101);
	int x;
	while(cin >> x) {
		cnt[x]++;
	}
	for(int i = 1; i <= 100; ++i) {
		while(cnt[i]--) {
			cout << i << " ";
		}
	}
	cout << "\n";
	return 0;
}

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© 若無特別註明,本站文章皆由 WeakMouse's Coding Blog 原創 ,轉載引用本文前請先留言告知。本文轉載請註明文章源自 WeakMouse's Coding Blog ,作者 ,並附上原文連結: 【題解】Zerojudge f282 - 松鼠的願望

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